Does the volume of juice extracted from red and green apples using the enzyme pectinase depends on the concentration of pectinase used, determined using volumetric analysis?
Application of biology in food industry and other food processing process is one of the most upcoming research topic. Use of enzymes in extracting juice from food samples is something, I studied in Molecular Biology and found really interesting. During my visit to a wine factory during one of our trips, I came to know the actual use of pectinase to process wine and make it clear by removing pectin from the wine. The questions that still bothered me was why are the manufacturers so particular about maintaining specific physical conditions like temperature, pH and concentrations of enzymes during this process. I came to know from my DP Biology classes that the action or catalytic ability of enzymes depends on physical conditions like temperature, pH and even concentration of both the substrate and the enzyme. I chose this field as a topic of investigation for my Biology Internal Assessment and arrived at the research question stated above.
Enzymes are macromolecular, globular proteins that act as biological catalysts in chemical reactions without having to be a part of the reaction and lower the activation energy when the enzyme and substrate bind. They are folded and form a pocket which serves as an active site in order to allow a substrate to bind which results in a reaction. The shape of the active site is complementary to that of the substrate and forms a lock and key structure which creates specificity for the enzyme. Since enzymes and substrates are in a continuous state of motion, they collide where the substrate binds to the active site of the enzyme creating an enzyme substrate complex. When substrates are inside the active site, the products formed are as a result of catabolism, which is the breaking of bonds or anabolism, which is the formation of bonds. After the reaction takes place, the products are released. In this experiment, the enzyme used is pectinase with the substrate being pectin.
There are several factors that affect the rate of enzymatic activity namely concentration between enzymes and their substrates, temperature and pH2 . This experiment will investigate the effect of different concentrations of pectinase on the production of fruit juice in red apples and green apples. As the enzyme concentration decreases, the rate of reaction will also decrease since there are not enough enzymes for substrates to bind to which inhibits a reaction to take place causing a decrease in enzymatic activity whereas when enzyme concentration increases, there will be more enzymes which will allow more substrates to bind to creating a higher number of reactions thus, increasing enzymatic activity.
Pectinase is an enzyme which break down pectin, a hetero polysaccharide present in the cell walls4 of fruits such as oranges and apples, and keeps the cell walls firm and rigid. As the enzyme breaks down the soluble pectin, the amylases take off starch from the juice which causes haze in the juice. Pectin gets broken down from polymers to monomers by the process of hydrolysis which are water-soluble, for example: breaking of glycosidic bonds between galacturonic acid. Pectinase is industrially used to extract juice from fruits by breaking through the cell walls, especially apples. Pectinase is found to show an optimum pH ranging from 3.5 to 9.12 and a range of temperature from 50.0oC to 90.0oC depending on the source of pectinase used5
There is no correlation between the volume of juice extracted from the red and green apples and the concentration of pectinase used for it. Any correlation observed is an outcome of an experimental error or by random chance.
There is a positive correlation between the volume of juice extracted from red and green apples and the concentration of pectinase used. The literature review (refer to Figure-2) supports this hypothesis.
The percentage concentration of pectinase used is the independent variable in this investigation. The pectinase solutions were prepared by dissolving pectinase (solid) in distilled water. The concentration has been measured in terms of mass percentage (mass of solute per 100 cm3 of the solvent). The solutions of pectinase used are – 10 %, 20 %, 30 %, 40 % and 50 % respectively. Digital mass balance was used to weigh the solid and the solutions were prepared in 100 cm3 volumetric flask.
The type of sample can also be considered as an independent variable for this investigation as two different varieties of apples were used – red apple and green apple.
The volume of clear juice obtained from the mesh of the fruits after adding pectinase to it is the dependent variable of this investigation. The volume was measured using a graduated measuring cylinder. Data were reported at a confidence level of ± 0.5 cm3.
Apparatus | Quantity | Least count | Uncertainty |
---|---|---|---|
Digital mass balance | 1 | 0.01 g | ±0.01 g |
Graduated measuring cylinder-100 cm3 | 1 | 1.0 cm3 | ±0.5 cm3 |
Spatula | 1 | NA | NA |
Watch glass | 1 | NA | NA |
100 cm3 volumetric flask | 5 | 100.00 cm3 | ±50 cm3 |
Knife | 1 | NA | NA |
Mixer grinder | 1 | NA | NA |
Stop-watch | 1 | 0.01 s | ±0.01 s |
Thermometer | 1 | 1.0oC | ±0.5 oC |
100 cm3 glass beaker | 5 | 20 cm3 | ± 10 cm3 |
Water bath | 1 | NA | NA |
Syringes – 10 cm3 | 1 | NA | NA |
Filter papers | 1 box | NA | NA |
Glass funnel | 1 | NA | NA |
10 cm3 graduated pipette | 1 | 0.10 cm3 | ±0.05 cm3 |
Volume % of solution | Volume of pectinase solution added / ±0.50 cm 3 | Volume of distilled water in cm3 |
---|---|---|
0.00 | 0.00 | 100.00 (Controlled) |
10.00 | 10.00 | 90.00 |
20.00 | 20.00 | 80.00 |
30.00 | 30.00 | 70.00 |
40.00 | 40.00 | 60.00 |
50.00 | 50.00 | 50.00 |
The required volume of pectinase was was transferred to a 100 cm3 clean and dry volumetric flask and distilled water was added to it using a graduated measuring cylinder.
For 10.00% pectinase solution,
Average= \(\frac{16.00+16.00+16.00+17.00+16.00}{5}= 16.20 ± 0.50 \, \,cm^3\)
Standard deviation
S.D = \(\frac{(16.00-16.20)^2 +(16.00-16.20)^2+(16.00-16.20)^2+(17.00-16.20)^2+(16.00-16.20)^2}{5}= 0.45\)
Mass percentage of pectinase solution | Average volume of juice extracted in ±0.50 cm3 | Fractional uncertainty | Percentage uncertainty |
---|---|---|---|
0.00 | 7.80 | 0.06 | 6.41 |
10.00 | 16.20 | 0.03 | 3.09 |
20.00 | 51.80 | 0.01 | 0.97 |
30.00 | 53.20 | 0.01 | 0.94 |
40.00 | 53.80 | 0.01 | 0.93 |
50.00 | 54.20 | 0.01 | 0.92 |
60.00 | 54.20 | 0.06 | 6.41 |